How do you write an equation of a line going through (-2,-3), (2,-1)?

1 Answer
May 10, 2017

y=1/2x-2

Explanation:

"the equation of a line in "color(blue)"slope-intercept form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))
where m represents the slope and b, the y-intercept.

"to calculate m, use the "color(blue)"gradient formula"

color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2=y_1)/(x_2-x_1))color(white)(2/2)|)))
where (x_1,y_1),(x_2,y_2)" are 2 coordinate points"

"the 2 points here are "(-2,-3)" and " (2,-1)

"let " (x_1,y_1)=(-2,-3)" and " (x_2,y_2)=(2,-1)

rArrm=(-1-(-3))/(2-(-2))=2/4=1/2

rArry=1/2x+blarr" is the partial equation"

"to find b, substitute either of the 2 given points into equation"

"using " (2,-1)

-1=(1/2xx2)+brArrb=-2

rArry=1/2x-2larrcolor(red)" in slope-intercept form"