How do you write an equation of a line with (-11,1), (-9,-3)?

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Answer 1 · 2016-03-05T10:59:35

$2x+y+21=0$

The equation of a line joining points $(x_1,y_1)$ and $(x_2,y_2)$ is given as

$(y-y_1)=((y_2-y_1)/(x_2-x_1))(x-x_1)$ .

Hence equation of a lie joining $(-11,1)$ and $(-9,-3)$ is given by

$(y-1)=(((-3)-1)/((-9)-(-11)))(x-(-11))$ or

$(y-1)=((-4)/(-9+11))(x+11)$ or

$(y-1)=((-4)/2)(x+11)$ or $(y-1)=(-2)(x+11)$ or

$y-1=-2x-22$ or $2x+y+21=0$