How do you write an equation of a line with point (1,5) slope -1?

1 Answer
Jun 27, 2017

See a solution process below:

Explanation:

The point-slope formula states: (y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))

Where color(blue)(m) is the slope and (color(red)(x_1, y_1)) is a point the line passes through.

Substituting the slope and values from the point in the problem gives:

(y - color(red)(5)) = color(blue)(-1)(x - color(red)(1))

We can solve for y to put the equation in slope-intercept form. The slope-intercept form of a linear equation is: y = color(red)(m)x + color(blue)(b)

Where color(red)(m) is the slope and color(blue)(b) is the y-intercept value.

y - color(red)(5) = (color(blue)(-1) xx x) - (color(blue)(-1) xx color(red)(1))

y - color(red)(5) = -1x - (-1)

y - color(red)(5) = -1x + 1

y - color(red)(5) + 5 = -1x + 1 + 5

y - 0 = -1x + 6

y = color(red)(-1)x + color(blue)(6)