How do you write an equation of a line with point (3,-2), slope 1/3?

1 Answer
Mar 22, 2017

See the entire solution process below:

Explanation:

The point-slope formula states: (y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))(yy1)=m(xx1)

Where color(blue)(m)m is the slope and color(red)(((x_1, y_1))) is a point the line passes through.

Substituting the values from the point and the slope given in the problems allows us to write this equation:

(y - color(red)(-2)) = color(blue)(1/3)(x - color(red)(3))

(y + color(red)(2)) = color(blue)(1/3)(x - color(red)(3))

We can also transform this to the slope-intercept form by solving for y. The slope-intercept form of a linear equation is: y = color(red)(m)x + color(blue)(b)

Where color(red)(m) is the slope and color(blue)(b) is the y-intercept value.

y + color(red)(2) = (color(blue)(1/3) xx x) - (color(blue)(1/3) xx color(red)(3))

y + color(red)(2) = 1/3x - 1

y + color(red)(2) - 2 = 1/3x - 1 - 2

y + 0 = 1/3x - 3

y = color(red)(1/3)x - color(blue)(3)