How do you write an equation of a line with points (-7,-3), (-3,5)?

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Answer 1 · 2017-04-15T21:18:45

$y = 2 x + 11$ $y = 2x + 11$

Put the equation in the $y = m x + b$ $y = mx + b$ form .

Find the slope of the equation by solving for

$m = \frac{y_{1} - y_{2}}{x_{1} - x_{2}}$ $m = ( y_1- y_2)/(x_1- x_2)$

Substituting the points for y and x gives

$m = \frac{- 3 - 5}{- 7 - (- 3)}$ $m = (-3 -5)/( -7 - (-3)$ = $- \frac{8}{- 4} = 2$ $-8/-4 = 2$

The slope: $m = 2$ $m = 2$

Putting $2$ $2$ in for $m$ $m$ and the values for $(x, y)$ $(x, y)$ gives

$5 = 2 (- 3) + b$ $5 = 2(-3) + b$ This results

# 5 = -6 + b add six to both sides

$5 + 6 = - 6 + 6 + b$ $5+ 6 = -6 +6 + b$

$11 = b$ $11 = b$

So the equation is $y = 2 x + 11$ $y = 2x + 11$