How do you write an equation of the line given (5, 2) and (-7, 3)?

1 Answer
Jan 31, 2017

(y - color(red)(2)) = color(blue)(-1/12)(x - color(red)(5))

Or

(y - color(red)(3)) = color(blue)(-1/12)(x + color(red)(7))

Or

y = -1/12x + 29/12

Explanation:

Given two points we can use the point-slope formula to find an equation for a line.

First, determine the slope. The slope can be found by using the formula: m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))

Where m is the slope and (color(blue)(x_1, y_1)) and (color(red)(x_2, y_2)) are the two points on the line.

Substituting the values from the points in the problem gives:

m = (color(red)(3) - color(blue)(2))/(color(red)(-7) - color(blue)(5))

m = 1/-12 = -1/12

The point-slope formula states: (y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))

Where color(blue)(m) is the slope and color(red)(((x_1, y_1))) is a point the line passes through.

We can use the first point and the slope we calculate to give:

(y - color(red)(2)) = color(blue)(-1/12)(x - color(red)(5))

We can also use the second point and the slope we calculate to give:

(y - color(red)(3)) = color(blue)(-1/12)(x - color(red)(-7))

(y - color(red)(3)) = color(blue)(-1/12)(x + color(red)(7))

We can also solve this for y to give an equation in slope-intercept form:

y - color(red)(3) = (color(blue)(-1/12) xx x) + (color(blue)(-1/12) xx color(red)(7))

y - color(red)(3) = color(blue)(-1/12)x - 7/12

y - color(red)(3) + 3 = color(blue)(-1/12)x - 7/12 + 3

y - 0 = color(blue)(-1/12)x - 7/12 + 36/12

y = -1/12x + 29/12