How do you write an equation that contains points (4, -1) and (-2, -13)?

1 Answer
Apr 20, 2018

y=2x-9

Explanation:

"the equation of a line in "color(blue)"slope-intercept form" is.

•color(white)(x)y=mx+b

"where m is the slope and b the y-intercept"

"to calculate m use the "color(blue)"gradient formula"

•color(white)(x)m=(y_2-y_1)/(x_2-x_1)

"let "(x_1,y_1)=(4,-1)" and "(x_2,y_2)=(-2,-13)

rArrm=(-13-(-1))/(-2-4)=(-12)/(-6)=2

rArry=2x+blarrcolor(blue)"is the partial equation"

"to find b substitute either of the 2 given points into"
"the partial equation"

"using "(4,-1)" then"

-1=8+brArrb=-1-8=-9

rArry=2x-9larrcolor(red)"is equation of line"