How do you write an equation that contains points (4, -1) and (-2, -13)?
1 Answer
Apr 20, 2018
Explanation:
"the equation of a line in "color(blue)"slope-intercept form" is.
•color(white)(x)y=mx+b
"where m is the slope and b the y-intercept"
"to calculate m use the "color(blue)"gradient formula"
•color(white)(x)m=(y_2-y_1)/(x_2-x_1)
"let "(x_1,y_1)=(4,-1)" and "(x_2,y_2)=(-2,-13)
rArrm=(-13-(-1))/(-2-4)=(-12)/(-6)=2
rArry=2x+blarrcolor(blue)"is the partial equation"
"to find b substitute either of the 2 given points into"
"the partial equation"
"using "(4,-1)" then"
-1=8+brArrb=-1-8=-9
rArry=2x-9larrcolor(red)"is equation of line"