How do you write the equation of the line that passes through (-6, -4) and (2, -5)?

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Answer 1 · 2016-06-02T13:46:41

You must first find the slope.

$m = (y_2 - y_1)/(x_2 - x_1)$

$m = (-5 - (-4))/(2 - (-6))$

$m = -1/8$

Now, use point slope form, one of your points and the slope that we found to convert the equation to slope intercept form, $y = mx + b$ .

$y - y_1 = m(x - x_1)$

$y - (-5) = -1/8(x -2)$

$y + 5 = -1/8x + 1/4$

$y = -1/8x -19/4$

You have your equation!

Hopefully this helps!