How do you write $e^(1/2)=1.6487$ in logarithmic form?

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Answer 1 · 2017-10-30T05:39:27

$e^(1/2)=1.6487 iff ln1.6487=1/2, or, 0.5.$

Recall that, $e^x=y iff lny=x.$

$:. e^(1/2)=1.6487 iff ln1.6487=1/2, or, 0.5.$

How do you write e^(1/2)=1.6487e^(1/2)=1.6487 in logarithmic form?