How do you write $lny = x ln2$ in exponential form?

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Answer 1 · 2015-09-26T21:20:56

Use the property of logs.

ln y = $ln 2^x$

Now, set each argument equal to each other:

$y = 2^x$

Hope that helped

How do you write lny = x ln2lny = x ln2 in exponential form?