Question

How do you write `log_125 25 = 2/3?` as an exponential form?

Answer 1

`25=125^(2/3)`

Explanation:

`"using the "color(blue)"law of logarithms"`

`•color(white)(x)log_b x=nhArrx=b^n`

`"here "b=125,x=25" and "n=2/3`

`rArrlog_(125) 25=2/3hArr25=125^(2/3)`