How do you write ${log}_{2} (64) = 6$ $log_2(64) = 6$ in exponential form.

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Answer 1 · 2015-02-11T23:15:36

In order to convert from logarithmic form to exponential form, you need to know the formula,

${log}_{a} x = y$ $log_ax = y$ is equaly equivalent to $a^{y} = x$ $a^y = x$

                       So you take

${log}_{2} 64 = 6$ $log_2 64 = 6$ and convert it to $2^{6} = 64$ $2^6 = 64$

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How do you write log2(64)=6log_2(64) = 6 in exponential form.