How do you write ${log}_{4} (32) = x$ $log_4(32)=x$ in exponential form?

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Answer 1 · 2015-11-07T20:05:58

I found: $32 = 4^{x}$ $32=4^x$

You can use the definition of log:

${log}_{a} b = x \to b = a^{x}$ $log_ab=x ->b=a^x$

so basically $4$ $4$ "pushes up" $x$ $x$ to becom an exponent and you get:
$32 = 4^{x}$ $32=4^x$

[You can get $x = 2.5$ $x=2.5$ in this case so that $32 = 4^{2.5}$ $32=4^(2.5)$ ]

How do you write log4(32)=xlog_4(32)=x in exponential form?