How do you write ${log}_{x} (64) = 3$ $log_x(64)=3$ in exponential form?

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How do you write ${log}_{x} (64) = 3$ $log_x(64)=3$ in exponential form?

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Answer 1 · 2018-05-09T12:37:49

$x^{3} = 64$ $x^3=64$

Explanation:

$using the law of logarithms$ $"using the "color(blue)"law of logarithms"$

$∙ x {log}_{b} x = n \Leftrightarrow x = b^{n}$ $•color(white)(x)log_b x=nhArrx=b^n$

$here x = 64, b = x and n = 3$ $"here "x=64,b=x" and "n=3$

$\Rightarrow {log}_{x} 64 = 3 \Rightarrow x^{3} = 64$ $rArrlog_x 64=3rArrx^3=64$

Answer 2 · 2018-05-09T13:12:13

$64 = 4^{3}$ $64=4^3$

Explanation:

${log}_{x} (64) = 3$ $log_x (64) = 3$

${log}_{x} (4^{3}) = 3$ $log_x (4^3 )=3$

$3 {log}_{x} 4 = 3 \to x = 4$ $3log_x 4 = 3 -> x=4$

Hence, we can express the identity in exponential form as: $64 = 4^{3}$ $64=4^3$

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How do you write ${log}_{x} (64) = 3$ $log_x(64)=3$ in exponential form?

2 Answers

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Explanation:

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Science

Math

Humanities

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How do you write log_x(64)=3logx(64)=3log_x(64)=3 in exponential form?

2 Answers

Explanation:

Explanation:

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How do you write ${log}_{x} (64) = 3$ $log_x(64)=3$ in exponential form?