How do you write the complex number in trigonometric form $-3-i$ ?

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Answer 1 · 2018-01-06T01:08:42

$sqrt10*Cis(pi+arctan(1/3))$

Magnitute of z=-3-i; $r=sqrt((-3)^2+(-1)^2)=sqrt10$

Argument of z; $Arg(z)=arctan((-1)/(-3))=arctan(1/3)$

However, z found in 3rd quadrant. Hence,

$z=sqrt10*Cis(pi+arctan(1/3))$

How do you write the complex number in trigonometric form -3-i-3-i?