How do you write the equation $(1/3)^-2=9$ in logarithmic form?

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Answer 1 · 2018-06-29T20:24:12

$-2 log(1/3) = log 9$

Take the log of both sides.

Left Hand Side: $log(1/3)^-2 = -2 log (1/3) = 2 log 3$

Right Hand Side: $log(9) = log(3^2) = 2 log 3$

How do you write the equation (1/3)^-2=9(1/3)^-2=9 in logarithmic form?