How do you write the equation $3x+2y-5=0$ in polar form?

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Answer 1 · 2017-05-06T12:30:33

$r=5/(3costheta+2sintheta)$

for polar coordinates we use the relations

#x^2+y^2=r^2

$x=rcostheta$

$y=rsintheta$

$3x+2y-5=0$

becomes

$3rcostheta+2rsintheta-5=0$

$r(3costheta+2sintheta)=5$

$r=5/(3costheta+2sintheta)$

How do you write the equation 3x+2y-5=03x+2y-5=0 in polar form?