How do you write the equation $α = sin β$ $alpha=sinbeta$ in the form of an inverse function?

Question

How do you write the equation $α = sin β$ $alpha=sinbeta$ in the form of an inverse function?

1 Answer

Related questions

How do you use the properties of inverse trigonometric functions to evaluate $tan (arcsin (0.31))$ $tan(arcsin (0.31))$ ?
What is $sin ({sin}^{- 1} \frac{\sqrt{2}}{2})$ $\sin ( sin^{-1} frac{sqrt{2}}{2})$ ?
How do you find the exact value of $cos ({tan}^{- 1} \sqrt{3})$ $\cos(tan^{-1}sqrt{3})$ ?
How do you evaluate ${sec}^{- 1} \sqrt{2}$ $\sec^{-1} \sqrt{2}$ ?
How do you find $cos ({cot}^{- 1} \sqrt{3})$ $cos( cot^{-1} sqrt{3} )$ without a calculator?
How do you rewrite ${sec}^{2} ({tan}^{- 1} x)$ $sec^2 (tan^{-1} x)$ in terms of x?
How do you use the inverse trigonometric properties to rewrite expressions in terms of x?
How do you calculate ${sin}^{- 1} (0.1)$ $sin^-1(0.1)$ ?
How do you solve the inverse trig function ${cos}^{- 1} (- \frac{\sqrt{2}}{2})$ $cos^-1 (-sqrt2/2)$ ?
How do you solve the inverse trig function $sin ({sin}^{- 1} (\frac{1}{3}))$ $sin(sin^-1 (1/3))$ ?

Impact of this question

1759 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-23T17:56:36

In the form of an inverse function $α = sin β$ $alpha=sinbeta$ can be written as $β = {sin}^{- 1} α$ $beta=sin^(-1)alpha$ or $β = arcsin α$ $beta=arcsinalpha$

Science

Math

Humanities

... and beyond

How do you write the equation $α = sin β$ $alpha=sinbeta$ in the form of an inverse function?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you write the equation alpha=sinbetaα=sinβalpha=sinbeta in the form of an inverse function?

1 Answer

Related questions

Impact of this question

How do you write the equation $α = sin β$ $alpha=sinbeta$ in the form of an inverse function?