How do you write the equation in point slope form given (8,7), (-2,-4)?

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Answer 1 · 2016-06-30T19:02:52

$y+4=11/10(x+2).$ [#pt.(-2,-4) used]

$y-7=11/10(x-8).$ [using #pt.(8,7)

Let the given pts. be $A(8,7), B(-2,-4).$

Then, by defn., slope of line $AB$ is, by defn., $(y_B-y_A)/(x_B-x_A)= (-4-7)/(-2-8)=-11/-10=11/10.$

Pt. $B(-2,-4)$ ies on Line $AB$

Hence, eqn. of line $AB,$ in slope-pt. form, using pt. $B(-2,-4),$ is :

$y-(-4)=11/10(x-(-2)),$ i.e., $y+4=11/10(x+2).$

One can choose pt. $A(8,7)$ to get the eqn. $y-7=11/10(x-8).$