How do you write the equation of the line with point (3, 6) and (0, –3) ?

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Answer 1 · 2016-07-26T13:56:14

The slope-intercept equation of the line would be $y=3x-3$

The slope-intercept form of the equation of the line is $y=mx+b$
where $m=$ slope and $b=$ the y intercept

Using the points (3,6) and (0,-3)

$m=(y_2-y_1)/(x_2-x_1)$

$x_1=3$
$y_1=6$
$x_2=0$
$y_2=-3$

$m = (-3-6)/(0-3)$

$m = (-9)/(-3)$

$m=3$

Now use the point slope formula to solve for the equation of the line.

$(y-y_1)=m(x-x_1)$

$m=3$
$x_1=0$
$y_1=-3$

$(y-y_1)=m(x-x_1)$

$(y-(-3))=-3(x-0)$

$y+3=-3x$

$y cancel(+3) cancel(-3)=3x -3$

$y=3x-3$