How do you write the equation tantheta=xtanθ=x in the form of an inverse function? Trigonometry Inverse Trigonometric Functions Inverse Trigonometric Properties 1 Answer sankarankalyanam Mar 17, 2018 theta = tan ^ -1 xθ=tan−1x Explanation: tan theta = xtanθ=x tan ^-1 (tan theta) = tan ^-1 xtan−1(tanθ)=tan−1x taking inverse on both sides. But tan ^-1 (tan theta) = thetatan−1(tanθ)=θ :. theta = tan ^ -1 x Answer link Related questions How do you use the properties of inverse trigonometric functions to evaluate tan(arcsin (0.31))? What is \sin ( sin^{-1} frac{sqrt{2}}{2})? How do you find the exact value of \cos(tan^{-1}sqrt{3})? How do you evaluate \sec^{-1} \sqrt{2} ? How do you find cos( cot^{-1} sqrt{3} ) without a calculator? How do you rewrite sec^2 (tan^{-1} x) in terms of x? How do you use the inverse trigonometric properties to rewrite expressions in terms of x? How do you calculate sin^-1(0.1)? How do you solve the inverse trig function cos^-1 (-sqrt2/2)? How do you solve the inverse trig function sin(sin^-1 (1/3))? See all questions in Inverse Trigonometric Properties Impact of this question 2141 views around the world You can reuse this answer Creative Commons License