How do you write the equation using function notation that goes through (-2,-5); perpendicular to $3x + 5y = -17$ ?

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Answer 1 · 2015-05-24T13:21:45

$3x+5y = -17$
can be written in slope-intercept form as
$y = -3/5x -71$
which has a slope of $-3/5$

Any line perpendicular to this will have a slope $5/3$

A line going through $(-2,-5)$ with a slope of $5/3$
is given by
$y+5 = 5/3(x+2)$

$y= (5x)/3 + 10/3 -5$

$y = (5x-5)/3 = 5/3(x-1)$
or
$f(x) = 5/3(x-1)$

How do you write the equation using function notation that goes through (-2,-5); perpendicular to 3x + 5y = -173x + 5y = -17?