How do you write the equation $x^2+y^2=-3x$ into polar form?

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Answer 1 · 2017-01-26T16:12:43

$r=-3costheta$

the conversion from Cartesian to polars

$r^2=x^2+y^2$

$x=rcostheta$

$y=rsintheta$

so we substitute into the eqn

$x^2+y^2=-3x$

$LHS=r^2$

$:.r^2=-3rcostheta$

divide through by $r$

$r=-3costheta$

How do you write the equation x^2+y^2=-3xx^2+y^2=-3x into polar form?