How do you write the equation $y - 1 = - 2 (x - 5)$ $y-1=-2(x-5)$ in slope intercept form?

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How do you write the equation $y - 1 = - 2 (x - 5)$ $y-1=-2(x-5)$ in slope intercept form?

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Answer 1 · 2017-07-29T02:26:26

Distribute the $- 2$ $-2$ to the $x$ $x$ and $- 5$ $-5$ , add $1$ $1$ to both sides of the equation.

Explanation:

Remember, slope-intercept form is represented as y=mx+b

Start on the right side of the equation, and distribute the $- 2$ $-2$ .
$- 2$ $-2$ times $x = - 2 x$ $x= -2x$ and $- 2 (- 5) = 10$ $-2(-5)=10$ .

Now we have the equation $y - 1 = - 2 x + 10$ $y-1= -2x+10$ . The only thing left to do is add $1$ $1$ to both sides of the equation so that the variable y is the only thing on the left side of the equation.

On the left hand side, the $- 1$ $-1$ and $+ 1$ $+1$ will cancel each other out, leaving the variable $y$ $y$ . On the right hand side, add $1$ $1$ to the $10$ $10$ only, to get $11$ $11$ **.

$y = - 2 x + 11$ $y=-2x+11$

We have obtained an equation in slope intercept form (y=mx+b), where $m = - 2 and b = 11$ $m=-2 and b=11$ .

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How do you write the equation $y - 1 = - 2 (x - 5)$ $y-1=-2(x-5)$ in slope intercept form?

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Explanation:

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How do you write the equation $y - 1 = - 2 (x - 5)$ $y-1=-2(x-5)$ in slope intercept form?