How do you write the equation $y - 1 = - 7 (x - 3)$ $y-1=-7(x-3)$ in slope intercept form?

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How do you write the equation $y - 1 = - 7 (x - 3)$ $y-1=-7(x-3)$ in slope intercept form?

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Answer 1 · 2018-03-20T20:10:34

$y = - 7 x + 22$ $y=-7x+22$

Explanation:

$the equation of a line in slope-intercept form$ $"the equation of a line in "color(blue)"slope-intercept form"$ is.

$∙ x y = m x + b$ $•color(white)(x)y=mx+b$

$where m is the slope and b the y-intercept$ $"where m is the slope and b the y-intercept"$

$y - 1 = - 7 (x - 3) \leftarrow distribute and rearrange$ $y-1=-7(x-3)larrcolor(blue)"distribute and rearrange"$

$y - 1 = - 7 x + 21$ $y-1=-7x+21$

$\Rightarrow y = - 7 x + 22 \leftarrow in slope-intercept form$ $rArry=-7x+22larrcolor(red)"in slope-intercept form"$

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How do you write the equation $y - 1 = - 7 (x - 3)$ $y-1=-7(x-3)$ in slope intercept form?

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Explanation:

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How do you write the equation y-1=-7(x-3)y−1=−7(x−3)y-1=-7(x-3) in slope intercept form?

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Explanation:

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How do you write the equation $y - 1 = - 7 (x - 3)$ $y-1=-7(x-3)$ in slope intercept form?