How do you write the equation $y - 2 = 3 (x - 1)$ $y-2=3(x-1)$ in slope intercept form?

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Answer 1 · 2017-02-11T02:57:05

$y = 3 x - 1$ $y = 3x - 1$

The slope-intercept form of a linear equation is: $y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

First, we need to expand the parenthesis on the right:

$y - 2 = (3 \times x) - (3 \times 1)$ $y - 2 = (3 xx x) - (3 xx 1)$

$y - 2 = 3 x - 3$ $y - 2 = 3x - 3$

Now, add $2$ $color(red)(2)$ to each side of the equation to solve for $y$ $y$ while keeping the equation balanced:

$y - 2 + 2 = 3 x - 3 + 2$ $y - 2 + color(red)(2) = 3x - 3 + color(red)(2)$

$y - 0 = 3 x - 1$ $y - 0 = 3x - 1$

$y = 3 x - 1$ $y = color(red)(3)x - color(blue)(1)$

How do you write the equation y-2=3(x-1)y−2=3(x−1)y-2=3(x-1) in slope intercept form?