Question

How do you write the lewis structure for `XeF_4`?

Answer 1

Well, there are 8 valence electrons around xenon.....

Explanation:

...and 7 valence electrons around each fluorine atom..

VESPER predicts an `AX_4E_2` structure, that is octahedral with respect to electronic geometry, and SQUARE planar with respect to molecular geometry. `/_F-Xe-F-=90^@` to a first approx.