Question

How do you write the noble-gas electron configuration for Ag?

Answer 1

Where is your Periodic Table?

Explanation:

For `"silver"`, `Z=47`. It is thus 11 protons removed from the last Noble Gas, which is `"krypton"`, `Z=36`.

And thus the electronic configuration of silver metal is: `[Kr]4d^(10)5s^1`. The `Ag(+I)` oxidation state can be rationalized on this basis.