How do you write the noble-gas electron configuration for B?

2 Answers
David Drayer
Oct 1, 2016

The noble gas configuration is the same for all elements (#s^2p^6#)
or in the case of Helium only (#s^2# )

Explanation:

B for Boron does not achieve the noble gas configuration by adding electrons so it does not reach the configuration of the noble gas Neon # Ne_10# (# 2s^2 2p^6#)

Boron achieves the noble gas configuration by losing electrons. So
# B_5^11# losing three electrons to achieve the noble gas configuration of #He_2^4# ( #1s^2#)

Ernest Z.
Oct 29, 2016

The noble gas electron configuration boron is #"[He]2s"^2 "2p"#.

Explanation:

Boron is element number 5 in the Periodic Table.

Thus, its electron configuration is #"1s"^2 "2s"^2 "2p"#.

The noble gas that comes before boron in the Periodic Table is helium.

Its electron configuration is #"1s"^2#.

Hence, the noble gas electron configuration of boron is #"[He]2s"^2 "2p"#.

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