How do you write the standard form of a line given (3, -3) and (5, 7)?

1 Answer
May 9, 2017

The equation of the line in standard form is y= 5x-y = 18

Explanation:

The slope of the line passing through (3,-3) and (5,7) is m= (y_2-y_1)/(x_2-x_1)= (7+3)/(5-3)=10/2 =5

Let the equation of the line in slope-intercept form be y=mx+c or y=5x+c

The point (3,-3) will satisfy the equation . So, -3= 5*3+c or c= -3-15= -18

Hence the equation of the line in slope-intercept form is y= 5x-18.

The equation of the line in standard form is y= 5x-y = 18 {Ans]