How do you write the standard form of a line given (3, 4) and (–3, –8)?

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How do you write the standard form of a line given (3, 4) and (–3, –8)?

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Answer 1 · 2018-03-05T21:49:14

$y = 2 x - 2$ $y=2x-2$

Explanation:

To find the equation of a line, first find the gradient.

$grad = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $"grad"=(y_2-y_1)/(x_2-x_1)$ for co-ordinates $(x_{1}, y_{1})$ $(x_1, y_1)$ and $(x_{2}, y_{2})$ $(x_2, y_2)$

$grad = \frac{- 8 - 4}{- 3 - 3}$ $"grad"=(-8-4)/(-3-3)$

$= \frac{- 12}{- 6}$ $=(-12)/(-6)$

$= 2$ $=2$

The equation of a line, gradient m, through $(x_{1}, y_{1})$ $(x_1, y_1)$ has the formula:

$y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$

$y - 4 = 2 (x - 3)$ $y-4=2(x-3)$

$y - 4 = 2 x - 6$ $y-4=2x-6$

$y = 2 x - 2$ $y=2x-2$

graph{y=2x-2 [-12.165, 7.835, -11.24, -1.24]}

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How do you write the standard form of a line given (3, 4) and (–3, –8)?

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