How do you write the standard form of a line given (3, 6) and (0, –3)?
1 Answer
Jan 30, 2017
y=3x-3
Explanation:
x_1=3
y_1=6
x_2=0
y_2=-3
(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)
(y-6)=(-3-6)/(0-3)(x-3)
y-6=(-9)/(-3)(x-3)
y-6=3(x-3)
y-6=3x-9
y=3x-9+6
y=3x-3
