How do you write the trigonometric form of 6?

1 Answer
Nov 7, 2016

I found: z=6[cos(π)+isin(π)]

Explanation:

We can "see" this number (z=6) on the Real axis on a complex plane:
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We need the angle θ and the modulus (length) to define the characteristics of our number in trig form as:
z=modulus[cos(θ)+isin(θ)]
observing our complex plane we see that:
modulus=6
θ=π=180
so ve get:
z=6[cos(π)+isin(π)]