How do you write the trigonometric form of $- 6$ $-6$ ?

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How do you write the trigonometric form of $- 6$ $-6$ ?

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Answer 1 · 2016-11-07T11:37:04

I found: $z = 6 [cos (π) + i sin (π)]$ $z=6[cos(pi)+isin(pi)]$

Explanation:

We can "see" this number ( $z = - 6$ $z=-6$ ) on the Real axis on a complex plane:
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We need the angle $θ$ $theta$ and the modulus (length) to define the characteristics of our number in trig form as:
$z = modulus [cos (θ) + i sin (θ)]$ $z="modulus"[cos(theta)+isin(theta)]$
observing our complex plane we see that:
modulus $= 6$ $=6$
$θ = π = 180^{\circ}$ $theta=pi=180^@$
so ve get:
$z = 6 [cos (π) + i sin (π)]$ $z=6[cos(pi)+isin(pi)]$

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How do you write the trigonometric form of $- 6$ $-6$ ?

1 Answer

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Science

Math

Humanities

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How do you write the trigonometric form of −6-6?

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Explanation:

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How do you write the trigonometric form of $- 6$ $-6$ ?