How do you write the vector equation that passes through point (1,0) and parallel to <-2,-4>?

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Answer 1 · 2016-12-08T09:48:07

$vecr=(lambda+1)veci-2vecj$

the vector eqn. of a line is given by

$vecr=veca+lambdavecd$

where

$vecr" "$ is the general vector point on the line

$veca" "$ is a known vector point on the line

$vecd" "$ is the direction of the line

$lamda" "$ is a scalar

in this case $veca=veci$

$vecd=2veci-4vecj$ or $veci-2vecj" "$ in its simplest form

$:.vecr=veci+lambda(veci-2vecj)=(lambda+1)veci-2vecj$