How do you write the vector equation that passes through point (1,0) and parallel to <-2,-4>?

1 Answer
Dec 8, 2016

vecr=(lambda+1)veci-2vecjr=(λ+1)i2j

Explanation:

the vector eqn. of a line is given by

vecr=veca+lambdavecdr=a+λd

where

vecr" "r is the general vector point on the line

veca" "a is a known vector point on the line

vecd" "d is the direction of the line

lamda" "λ is a scalar

in this case veca=vecia=i

vecd=2veci-4vecj d=2i4jor veci-2vecj" "i2j in its simplest form

:.vecr=veci+lambda(veci-2vecj)=(lambda+1)veci-2vecj