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How do you write $y = - 2 {(x + 1)}^{2} + 3$ $y=-2(x+1)^2 +3$ in standard form?

1 Answer

Jun 15, 2015

In standard form: $y = - 2 x^{2} - 4 x + 1$ $y = -2x^2-4x +1$

Explanation:

Standard form for a quadratic is
$XXXX$ $color(white)("XXXX")$ $y = a x^{2} + b x + c$ $y = ax^2+bx+c$

$y = - 2 {(x + 1)}^{2} + 3$ $y = -2(x+1)^2+3$
can be expanded as
$XXXX$ $color(white)("XXXX")$ $y = (- 2) (x^{2} + 2 x + 1) + 3$ $y=(-2)(x^2+2x+1)+3$

$XXXX$ $color(white)("XXXX")$ $y = - (- 2 x^{2} - 4 x - 2) + 3$ $y=-(-2x^2 -4x -2)+3$

$XXXX$ $color(white)("XXXX")$ $y = - 2 x^{2} - 4 x + 1$ $y=-2x^2 -4x +1$

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