Question

How long it takes the arrow to come back to the ground if Andrew is an avid archer and he launches an arrow that takes a parabolic path, modeled by the equation `y=-4.9t^2+48t`?

Answer 1

Since `y=0` at the ground level, we have

`0=-4.9t^2+48t=t(-4.9t+48)`

`=> {(t=0),(t=48/4.9 approx 9.8):}`

Hence, it takes approximately `9.8` s.

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I hope that this was helpful.