How many atoms are in 1.92 mol $KMnO_4$ ?

Question

1619 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-03T13:22:19

$1$ $mol$ of particles specifies Avogadro's number of particles, so $"no. of atoms" = N_Axx1.92*molxx6" atoms "mol^-1*KMnO_4$ .

So, $N_A$ , Avogadro's number, specifies $6.022xx10^23$ $mol^-1$ .

You have quoted a $1.92$ $"mole"$ quantity. This specifies $1.92$ $"mole"$ $xx$ $6.022xx10^23$ $mol^-1$ individual $KMnO_4$ units.

Now each $KMnO_4$ unit comprises $6$ atoms. So simply multiply the molar quantity by 6

How many atoms are in 1.92 mol KMnO_4KMnO_4?