Question

How many atoms are in 33 g of titanium (Ti)?

Answer 1

Approx. `4xx10^23` individual titanium atoms..........

Explanation:

We work out the molar quantity of titanium metal:

`"Moles of titanium"` `=` `(33*g)/(47.9*g*mol^-1)~=0.70*mol`

Note that this quotient is dimensionally consistent. We wanted an answer in `"moles"`, we got the quotient with units of:

`cancelg/(cancelg*mol^-1)=1/(mol^-1)=1/(1/(mol))=mol` as required...... Capisce?

And then we multiply this molar quantity by `"Avogadro's number"`, which is `6.022xx10^23*mol^-1` (and the number of titanium atoms has a mass of `47.9*g` by definition).

`"Number of titanium atoms"=6.022xx10^23*mol^-1xx0.7*mol`

`~=4.0xx10^23`