How many grams are in 4.1 moles of $CO_2$ ?

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Answer 1 · 2016-01-20T19:27:33

$m=180.4g$

The relationship between the mass and number of mole is giving by:

$n=m/(MM)$

where, $n$ is the number of mole
$m$ is the mass of the compound
and $MM$ is the molar mass

$=>m=nxxMM=4.1cancel(mol)xx44g/(cancel(mol))=180.4g$

How many grams are in 4.1 moles of CO_2CO_2?