Question

How many grams of `NaOH` are in 500 mL of 0.175 M `NaOH` solution?

Answer 1

Under `4.0*g` of sodium hydroxide.

Explanation:

`"Concentration"` `=` `"Moles"/"Volume of solution"`.

Thus `n_"NaOH"` `=` `500xx10^-3cancelLxx0.175*mol*cancel(L^-1)=0.0875*mol`. (i.e., `"moles"` `=` `"volume "xx" concentration"`); this is certainly consistent dimensionally.

We thus have a quantity in moles of `NaOH`. All we have to do is multiply this molar quantity by the molar mass:

`40.00*g*cancel(mol^-1)xx0.0875*cancel(mol)` `=` `??g`