How many mL of 0.200 M HCI are needed to neutralize 20.0 mL of 0.150 M #Ba(OH)_2#?

1 Answer
anor277
May 13, 2017

Approx. #-=60*mL#

Explanation:

We use the relationship: #"Moles of stuff"/"Volume of solution"="Molarity"#.

There are #2xx20xx10^-3*Lxx0.150*mol*L^-1=6.00xx10^-3*mol# #Ba(OH)_2#, and this is neutralized according to the following equation:

#Ba(OH)_2(s) + 2HCl(aq)rarrBaCl_2(aq) + 2H_2O(l)#

Given the #"STOICHIOMETRY"#, we need 2 equiv of hydrochloric acid, and given #0.200*mol*L^-1# #HCl(aq)# we need a volume of..........

#(6.00xx10^-3*cancel(mol)xx2)/(0.200*cancel(mol)*L^-1)=0.0600*L#

#-=60*mL#

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