How many molecules are in 4.5 L of $C O_{2}$ $CO_2$ at STP?

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How many molecules are in 4.5 L of $C O_{2}$ $CO_2$ at STP?

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Answer 1 · 2016-05-01T10:22:49

$\frac{4.5 \cdot L}{22.4 \cdot L \cdot m o l^{- 1}}$ $(4.5*L)/(22.4*L*mol^-1)$ $\times$ $xx$ $N_{A}$ $N_A$ , where $N_{A} = Avogadro's number$ $N_A =" Avogadro's number"$

Explanation:

We assume ideality, and recall that at $STP$ $"STP"$ 1 mole of ideal gas occupies a volume of $22.4 \cdot L$ $22.4*L$ . We also know that $N_{A} = Avogadro's number$ $N_A =" Avogadro's number"$ $=$ $=$ $6.02214 \times 10^{23} \cdot m o l^{- 1}$ $6.02214xx10^23*mol^-1$

So $\frac{4.5 \cdot L}{22.4 \cdot L \cdot m o l^{- 1}}$ $(4.5*L)/(22.4*L*mol^-1)$ $\times$ $xx$ $6.02214 \times 10^{23} \cdot m o l^{- 1}$ $6.02214xx10^23*mol^-1$ $=$ $=$

$approx. \frac{1}{5} \times N_{A} ?$ $"approx. "1/5xxN_A?$

You can do the arithmetic.

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How many molecules are in 4.5 L of $C O_{2}$ $CO_2$ at STP?

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