How many moles are in 5.96 g $KOH$ ?

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Answer 1 · 2016-03-06T16:21:36

Approx. $1/10" moles"$

Potassium hydroxide has a molar mass of $56.11$ $g*mol^-1$ .

To get the molar quantity we simply take the quotient:

$n$ = $"Mass"/"Molar mass"$ $=$ $(5.96*cancelg)/(56.11*cancelg*mol^-1)$ $=$ $?? mol$

How many moles are in 5.96 g KOHKOH?