How many mols are in 23.7 g of $KMnO_4$ ?

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Answer 1 · 2016-11-15T17:35:53

$"Number of moles"$ $=$ $"Mass"/"Molar mass"$

And moles of $"potassium permanganate"$ $=$ $(23.7*g)/(158.03*g*mol^-1)$ $~=1/6*mol$ .

How many moles of oxygen atoms does this represent?

How many mols are in 23.7 g of KMnO_4KMnO_4?