How many quantum numbers are needed to define the probability of finding the electron in a given region of space in the hydrogen atom?

1 Answer
Feb 14, 2016

Three: n, l, and m_l.

We need the quantum level of the orbital, the shape/type (s, p, d, etc) of the orbital, and which of those orbitals it is in (e.g. p_x, p_y, or p_z for p orbitals).


PROBABILITY DENSITY

The probability density of an electron in an atomic orbital is defined as the statistical distribution of where an electron often appears in that orbital.

Probability density is defined as:

int_"allspace" psi^"*"psid tau

where:

  • psi is the wave function that describes the state of a quantum mechanical system such as an atom or molecule.
  • psi^"*" is its complex conjugate; since Real Chemists™ use real numbers, psi^"*" = psi.
  • "allspace" means the inclusion of all possible (finite) locations in space.

PROBABILITY DENSITY FOR THE HYDROGEN ATOM

For the hydrogen atom, which uses spherical coordinates (vecr,theta,phi), the wave function psi can be split into two components: the radial and angular components, R_(nl)(vecr) and Y_(l)^(m_l)(theta,phi), respectively.

\mathbf(psi(vecr,theta,phi) = R_(nl)(vecr)Y_(l)^(m_l)(theta,phi))

From this, the probability density is written as:

int_"allspace" psi^"*"(vecr,theta,phi)psi(vecr,theta,phi) d tau = stackrel("Radial Component")overbrace(int_(0)^(oo) R_(nl)^2(vecr)r^2dr) stackrel("Angular Component")overbrace(int_(0)^(pi) (Y_(l)^(m_l)(theta))^2sinthetad theta int_(0)^(2pi) (Y_(l)^(m_l)(phi))^2dphi)

  • The radial component contains the quantum numbers n (quantum level, such as n = color(blue)(3) for the color(blue)(3)s atomic orbital, etc) and l (the angular momentum, which for instance is l = color(blue)(2) for a color(blue)(d) orbital).
  • vecr is the radial distance (outwards in all directions).
  • The angular component essentially sweeps out the changes away from spherical uniformity. For instance, an s orbital has a constant theta and phi, so it is a sphere. A p orbital is not a sphere, so it has theta and phi dependence.
  • theta is the angle from the \mathbf(z) axis (vertical) going clockwise towards the x axis (horizontal), and phi is the angle from the \mathbf(y) axis (towards you) going counterclockwise (on the xy-plane).

WHAT DO WE PLOT?

For simplicity, we often don't plot Y_(l)^(m_l)(theta,phi). We choose to plot the radial density distribution by using only the radial component.

Therefore, it is a graph of vecr^2R_(nl)^2(vecr) vs. vecr with x-axis units of a_0 = 5.29177xx10^(-11) "m", as shown below for a 2s orbital:

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TAKE-HOME MESSAGE

Since R_(nl)(vecr) uses the quantum numbers n and l, and Y_(l)^(m_l)(theta,phi) uses the quantum numbers l and m_l, we need:

  1. n to show the quantum level of the orbital that the electron might be found in.
  2. l to show the shape of the orbital that the electron might be found in.
  3. m_l to determine which of the 2l + 1 orbitals (m_l = 0, pm1, . . . , pml) the electron might be found in.