How many solutions are there for the equation $x^2 + 16 = 8x$ ?

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Answer 1 · 2016-04-21T12:49:19

! solution only. Which is $x=4$

Subtract $8x$ from both sides

$x^2-8x+16=0$

Note that $(-4)xx(-4) = +16" and "(-4)+(-4)=-8$

So we have:

$(x-4)(x-4)=0" "->" "(x-4)^2=0$

The only solution is $x=(+4)$

How many solutions are there for the equation x^2 + 16 = 8xx^2 + 16 = 8x?