How many total atoms are in 0.410 g of $P_2O_5?$

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Answer 1 · 2016-10-02T12:06:41

Approx. $126xx10^20*"atoms of phosphorus and oxygen."$

$P_2O_5$ has a molar mass of $141.94*g*mol^-1$ .

And thus there is a molar quantity of $(0.410*g)/(141.95*g*mol^-1)$ $=$ $2.89xx10^-3*mol$ .

Because there are $6.022xx10^23$ particles in a mole by definition, there are thus,

$2.89xx10^-3*molxx6.022xx10^23*mol^-1xx7*"atoms"$

$=$ $"how many atoms"$ .

Note the actual molecule is $P_4O_10$ ; had I worked out the problem with this formulation I would have got precisely the same result.

How many total atoms are in 0.410 g of P_2O_5?P_2O_5?