How much greater is $(- 13 x^{2} - 13 x - 10) + (19 x^{2} - 19 x - 5)$ $(-13x^2 - 13x - 10) + (19x^2 - 19x - 5)$ ?

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How much greater is $(- 13 x^{2} - 13 x - 10) + (19 x^{2} - 19 x - 5)$ $(-13x^2 - 13x - 10) + (19x^2 - 19x - 5)$ ?

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Answer 1 · 2015-06-19T05:42:48

Answer 1: $= - 32 x^{2} + 6 x - 5$ $=color(red)(-32x^2 + 6x-5$
Answer 2: $= 6 x^{2} - 32 x - 15$ $= color(red)(6x^2) color(blue)(-32x) -15$

Explanation:

There are two ways of interpreting this question

How much greater is $- 13 x^{2} - 13 x - 10$ $-13x^2 - 13x - 10$ than $19 x^{2} - 19 x - 5$ $19x^2 - 19x -5$

Here we need to subtract:
$- 13 x^{2} - 13 x - 10$ $-13x^2 - 13x - 10$
$- 19 x^{2} + 19 x + 5$ $color(red)(-)19x^2 color(red)(+) 19x color(red)(+)5$
$= - 32 x^{2} + 6 x - 5$ $=color(red)(-32x^2 + 6x-5$

2.The second way is by adding the two as addition $+$ $color(green)(+$ has been mentioned in the question.

$- 13 x^{2} - 13 x - 10 + 19 x^{2} - 19 x - 5$ $-13x^2 - 13x - 10 + 19x^2 - 19x -5$

grouping like terms
$= (- 13 x^{2} + 19 x^{2}) + (- 13 x - 19 x) + (- 10 - 5)$ $= color(red)((-13 x^2 + 19x^2)) + color(blue)((-13x - 19x)) + (-10 - 5)$
$= 6 x^{2} - 32 x - 15$ $= color(red)(6x^2) color(blue)(-32x) -15$

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How much greater is $(- 13 x^{2} - 13 x - 10) + (19 x^{2} - 19 x - 5)$ $(-13x^2 - 13x - 10) + (19x^2 - 19x - 5)$ ?

1 Answer

Explanation:

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How much greater is (−13x2−13x−10)+(19x2−19x−5)(-13x^2 - 13x - 10) + (19x^2 - 19x - 5)?

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Explanation:

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How much greater is $(- 13 x^{2} - 13 x - 10) + (19 x^{2} - 19 x - 5)$ $(-13x^2 - 13x - 10) + (19x^2 - 19x - 5)$ ?