How much greater is $(-20x^2 + 13x - 4)$ than $(11x^2 - 13x - 10)$ ?

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Answer 1 · 2018-05-16T21:44:29

$=-31x^2+26x+6$

Consider the question. How much is $20$ greater than $16?$

We would do $20-16 =4$

In the same way.....

How much greater is $(-20x^2 + 13x - 4)$ than $(11x^2 - 13x - 10)$ will be done as a subtraction.

$rarr(-20x^2 + 13x - 4) -(11x^2 - 13x - 10)$

$= -20x^2 + 13x - 4 -11x^2 + 13x + 10" "larr$ notice the signs

$=-31x^2+26x+6$

How much greater is (-20x^2 + 13x - 4)(-20x^2 + 13x - 4) than (11x^2 - 13x - 10)(11x^2 - 13x - 10)?