How to find domain and range of say: $y = 1/(x^2 - 2)$ ?

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Answer 1 · 2018-04-19T02:52:05

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$y=1/(x^2-2)$

$y=1/((x-sqrt2)(x+sqrt2))$

Domain: all reals except when $x=-sqrt2$ and $x=sqrt2$

Range: all reals except $-1/2 < y < 0$

graph{1/(x^2-2) [-10, 10, -5, 5]}

How to find domain and range of say: y = 1/(x^2 - 2)y = 1/(x^2 - 2)?